how to use just two of the simplification commands of Mathematica. In the end i want to have the requests minus the onhand but the requests are different to each others IDs as they will have different due dates and quantities. How do I simplify this code (remove for loop). Power Conversion of Renewable Energy Systems aims to instruct readers how to actively apply the theories discussed within.
I tried using for loops with if else statements to take the onhand and subtract it one at a time until it is zero. Applications of PSpice, MATLAB, and Mathematica are also included, along with solutions to over 100 application examples. It should result in something like this: ID Type Quantity Type<-c("Onhand","Requested","Onhand","Requested","Requested","Onhand","Requested","Onhand") This should then make onhand=0 then request 1 should be 0 and then request 2 should be 30. I made dummy data to create a function to remove stock from stock on hand but i am having trouble with R,i don't know which loops to use? It should take i.e onhand is 50 with a request for 30 and another request for 50. This video demonstrates the detailed description and basic concept of various loops such as IF loop, FOR loop and DO loop. I have dataset of stock on hand and requests for stock.
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